above ans is correct i also solve it ans is 6
The above ans is correct .
Let us make it more clear : Ans. a/(b+c+d)+1+b/(c+d+e)+1+c/(d+a+b)+1+d/(a+b+c)+1-4 =(a+b+c+d){1/(b+c+d)........}-4=6×5/3 -4=10-4=6 .
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Hello, You have asked an important question from the Arithmetic part in mathematics,as this is the most important topic from the JEE Point of View As the JEE Advanced 2018 Date is out The Arithmetic part covers good weight age in JEE Exams The JEE Advanced date is out Is going to be conducted on 20th May.
If f''(x) = f(x), f(0)=2, f'(0)=3, then find area bounded by the curve f(x) between the axes.
(A)- 3 (B)- 3-5^(0.5) (C)- 3-0.5xln5 (D)- 2+0.5xln5