If f''(x) = f(x), f(0)=2, f'(0)=3, then find area bounded by the curve f(x) between the axes.

(A)- 3

(B)- 3-5^(0.5)

(C)- 3-0.5xln5

(D)- 2+0.5xln5

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If f''(x) = f(x), f(0)=2, f'(0)=3, then find area bounded by the curve f(x) between the axes.

(A)- 3

(B)- 3-5^(0.5)

(C)- 3-0.5xln5

(D)- 2+0.5xln5

0 votes

Simply D^2y-y=0 . Therefore by solving complementary eqn. m^2y-y=0 **get the roots m1 and m2 equal to 1 and -1 . The general soln is
Ae^x+Be^-x . Put the values of y=f(0)=2 and f'(0)=0 we get A=5/2 , **strong text**B=-1/2 . Putting y=0 we get x= -0.5ln5 . Taking integration from x=-0.5ln5 to x=0 we get area A=sqrt5-3 . The options given are incorrect .**strong text****

Hope this will serve your purpose .

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